Dear LLLLLLLLLL,
The Answers are put under each question below. These Q&A
will be posted on the blog also.
Best,
HS Kwan
-----Original Message-----
From: LLLLLLLLLLLL
Sent: Wednesday, October 29, 2014 10:51 PM
To: hoishankwan@cuhk.edu.hk
Subject: FNSC 5110 questions
Dear Professor Kwan,
I have several questions about the sample midterm that I
have been struggling with, and it’d be great if you could clarify the following
for me:
1. Calculation for attack rates
Is the attack
rate just basically the # of ill / total #
A: We have not discussed this
topic in the class. Not included in the exam.
2. Question on the exam is: What are the F values set in
the canning process for these target microorganisms?) I know that for low acid
canned foods (pH>4.5), the calculation for F values is F = 12D. However, the
exam asks for F values at pH 4.0 and 4.5. What approach should I take?
A: The F values now is set as
the number of D attained in the process. If the process was designed for pH4.0,
use the D for pH4.0 to calculate F.
3. Question on the exam is: What are the number of D's
that actually occurred in the problematic canning process for these target
microorganisms?
I am not too
sure about what the question is asking for. Dose it mean how many fold-decrease
for each of the microbial (spoilage bacteria, bacterial spores, and fungal
spores) occurred for 20 minutes at 105 degree C of processing (10 min per one
time of processing, and the canned pig knuckles with incorrectly reported pH
were processed twice) ?
A: Yes.
4. Question on the exam is: What would be the cell
densities of the microorganisms in the processed pickled pigknuckles with
actual pH of 4.0 after they were processed for 10 minutes at 105 degree C?
Do I basically
just calculate the number of fold-decrease using the known D value for microbes
at pH 4.0, and then divide the approximate microbial flora in picked pig
knuckles by the fold-decrease?
e.g. Spoilage bacteria (D value at 105 degree C) = 0.001
minutes
That means
there’s a 10-fold decrease in 0.001 minutes. So in 10 minutes, there is a
100,000 fold-decrease.
Approximate
spoilage bacteria in pickled pig knuckles = 1000/mL
So 100,000
fold-decrease results in 0.01/mL after 10 minutes treatment at 105 degree C I
felt like the calculations are wrong, because it happened that none of the
microbial flora decreased to an acceptable cell density after treatment. Please
let me know if I have misinterpreted anything.
A: Your calculation approach is
basically correct. But 10/0.001=10,000, not 100,000. The decrease is log decrease, not fold decrease. A 10,000 log decrease of
1000/ml-->1000x10<-10>=10<-997> definitely blow the
acceptable cell density. You need to know how to calculate.
Thank you very much for you attention, and I hope to hear
back from you soon!
Best Regards,